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g(x)

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g(x)

by ST » Tue May 26, 2009 6:24 am
could someone please explain this?

thank you

ST
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by truplayer256 » Tue May 26, 2009 6:35 am
g(2)=[(2)^(2)+2]/2-1=6
(1/g(2))*(1/g(x))=1/6*(x-1/x^2+2)=(x-1)/6(x^2+2)
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just wondering

by ST » Tue May 26, 2009 6:59 am
why did you choose 2 for g(x) rather then any other number? What about if you could have used 3 or 10 or even -5.

St
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by truplayer256 » Tue May 26, 2009 7:01 am
why did you choose 2 for g(x) rather then any other number? What about if you could have used 3 or 10 or even -5.
Because the questions asks you for g(2).
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that's right

by ST » Tue May 26, 2009 7:07 am
that's right. I missed that....:)

thanks

ST
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