NandishSS wrote:The ratio of water and ammonia in solution A is 1 : 4; the ratio of the same two substances in solution B is 3 : 1. If solutions A and B are mixed, what will be the ratio of water and ammonia in the resultant solution?
(1) Solutions A and B are mixed in ratio 2 : 3.
(2) 20 liters of solution A is used
Question stem, rephrased:
What fraction of the resultant solution is water?
Statement 1:
Case 1: A=20 liters and B=30 liters, for a total of 50 liters
Since A is 1/5 water, the amount of water in 20 liters of A = (1/5)(20) = 4.
Since B is 3/4 water, the amount of water in 30 liters of B = (3/4)(30) = 22.5.
Thus, (total water)/(total volume) = (4 + 22.5)/50 = 26.5/50 = 53/100.
Case 2: A=40 liters and B=60 liters, for a total of 100 liters
Since A is 1/5 water, the amount of water in 40 liters of A = (1/5)(40) = 8.
Since B is 3/4 water, the amount of water in 60 liters of B = (3/4)(60) = 45.
Thus, (total water)/(total volume) = (8 + 45)/100 = 53/100.
Since (total water)/(total volume) is THE SAME VALUE in each case -- 53/100 --
Statement 1 is SUFFICIENT.
Statement 2:
No information about the amount of B in the resultant solution.
INSUFFICIENT.
The correct answer is
A.
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