Not able to solve this Problem. Pls help...

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Darlene averaged a score of 70 out of 110 on evaluations from 1/3 of her supervisors. If Darlene wishes to average a score of 90 out of 110 on all of her evaluations, by approximately what percent must her average score increase on the remaining 2/3 of the evaluations?

A. 20%
B. 28%
C. 30%
D. 43%
E. 50%

OA is D

I am not able to solve this question. Just getting mixed into different equations.
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by knight247 » Wed Nov 16, 2011 6:15 am
The quickest method is by using weighted averages
Present score is (70/110) whose 'weight' is 1/3

Final required score is 90/110 which is the weighted average

The score in the remaining 2/3 tests is x/110 and the 'weight' is 2/3
So we have,

(1/3)(70/110) + (2/3)(x/110)=90/110

Solving for x we get x=100/110
Which means she needs to increase her score from 70 to 100 i.e. (100-70)/70= 42.sumthing ≈ 43 Hence D

This was the fastest way to solve. Lemme know if u need an alternate explanation. Cheers

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by GMATGuruNY » Wed Nov 16, 2011 8:03 am
Viren1808 wrote:Darlene averaged a score of 70 out of 110 on evaluations from 1/3 of her supervisors. If Darlene wishes to average a score of 90 out of 110 on all of her evaluations, by approximately what percent must her average score increase on the remaining 2/3 of the evaluations?

A. 20%
B. 28%
C. 30%
D. 43%
E. 50%

OA is D

I am not able to solve this question. Just getting mixed into different equations.
Let the number of supervisors = 3.
For the average score to be 90, the total number of points required = 3*90 = 270.
1 supervisor -- 1/3 of the total number of supervisors -- gave Darlene a score of 70.
Thus, the total number of points required from the other 2 supervisors = 270-70 = 200.
The average number of points required from these 2 supervisors = 200/2 = 100.
Percent increase from 70 to 100 = (100-70)/70 * 100 ≈ 43.

The correct answer is D.
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