Plane Problem

This topic has expert replies
Junior | Next Rank: 30 Posts
Posts: 15
Joined: Sun Jun 08, 2008 5:12 pm

Plane Problem

by ssraf » Thu Jun 12, 2008 4:26 pm
For any point T in the xy-plane, the centre of T is defined to be the point whose x-coordinate is the average of the x-coordinates of the vertices of T, and whose y-coordinate is the average of the y-coordinates of the vertices of T. If a triangle has vertices (0,0) and (6,0) and its centre at (3,2), what are the coordinates of the remaining vertice?

(3,4)
(3,6)
(4,9)
(6,4)
(9,6)

OA is B, shouldn't it be A????
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 2623
Joined: Mon Jun 02, 2008 3:17 am
Location: Montreal
Thanked: 1090 times
Followed by:355 members
GMAT Score:780

Re: Plane Problem

by Ian Stewart » Thu Jun 12, 2008 4:46 pm
ssraf wrote:For any point T in the xy-plane, the centre of T is defined to be the point whose x-coordinate is the average of the x-coordinates of the vertices of T, and whose y-coordinate is the average of the y-coordinates of the vertices of T. If a triangle has vertices (0,0) and (6,0) and its centre at (3,2), what are the coordinates of the remaining vertice?

(3,4)
(3,6)
(4,9)
(6,4)
(9,6)

OA is B, shouldn't it be A????
The center, (3,2), is the average of the co-ordinates of the three vertices of the triangle, (0,0), (6,0), and some unknown point, let's say (c, d). So, averaging x-co-ordinates:

3 = (0+6+c)/3
9 = 6 + c
3 = c

and averaging y-co-ordinates

2 = (0+0+d)/3
6 = d

So the remaining vertex is (3, 6).