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x>y ds q

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x>y ds q

by tj123 » Sun May 31, 2009 10:10 pm
is x>y?

1) x+y<0

2)x-y>0

OAb

[spoiler] please explain why statement 1 is not suff. If x = -3 and y = -2 then the answer is false, hence suff right? [/spoiler]
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by raleigh » Sun May 31, 2009 10:29 pm
Is x>y?

1) x+y<0

2)x-y>0


(1) x + y < 0. The only manipulation you can get from this is that x < -y. This doesn't seem like much help so let's produce a counter example.

Choose x = -1, y = -2. Then x + y = -3 < 0 and x > y.
Choose x = -2, y = -1. Then x + y = -3 < 0 and x < y.

This is insufficient.

(2) x - y > 0. Add y to both sides and we get x > y. This is sufficient. The answer is B.
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by aj5105 » Sun May 31, 2009 10:45 pm
(B)
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