-
ithamarsorek
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Tue Dec 07, 2010 1:01 pm
let the number of representatives be p, q, r, s, A and t such that
p<q<r<s<A<t
p+q+r+s+A+t = 75
(i) 41 has to be the greatest number of representatives from a country [because (41+ a number greater than 41) >75]
so t must be 41.
remaining # of representatives = 75-41 = 34
let's see if a solution is possible with at least 10 from A
4+5+6+7 + 12 +41 ---> A = 12; YES country A sent at least 10
let's see if a solution is possible with less than 10 representative from A
4+6+7+8+9+41; No country A sent fewer than 10
=> statement (i) not sufficient alone
(ii) A < 12
1+2+3+4 + 11 + 54; YES country A sent at least 10
1+2+3+4 + 5 + 60; NO country A sent fewer than 10.
=> statement (ii) not sufficient alone
combining the two -
possible solutions are
4+5+6+8+11+41 --> yes A sent greater than 10
4+6+7+8+9+41 --> no A sent fewer than 10
Thus two together are not sufficient --> Answer E
