can u post the OA pls...erukumk wrote:is |X| < 1?
1) |X+1|=2|X-1|
2)|X-3|!=0
Is it C?
Question can be paraphrased as:erukumk wrote:is |X| < 1?
1) |X+1|=2|X-1|
2)|X-3|!=0
Correct me if I'm wrong here:logitech wrote: 2) IX-3|!=0
|X-3|!=0 , 0! = 0
Means that X=3
3 is not between -1 and + 1
Sufficient
Hence, B
|x-3|!=0bluementor wrote:Correct me if I'm wrong here:logitech wrote: 2) IX-3|!=0
|X-3|!=0 , 0! = 0
Means that X=3
3 is not between -1 and + 1
Sufficient
Hence, B
|x-3|!=0 simply means x !=3. Therefore, x could lie between -1 and 1 or it could be anything else, except 3. So this statement is not sufficient.
-BM-
x != 0 means x not equal to 0.logitech wrote:
|x-3|!=0
Okay I just checked it and The factorial 0! evaluates to 1.
So this disproves my solution. I don't know what |x-3|!=0 means!
it does not make any sense my friend.bluementor wrote:x != 0 means x not equal to 0.logitech wrote:
|x-3|!=0
Okay I just checked it and The factorial 0! evaluates to 1.
So this disproves my solution. I don't know what |x-3|!=0 means!
-BM-
Well, we don't know what x is. All we know about x is that its not equal to 0. Thats what x != 0 means.logitech wrote:it does not make any sense my friend.bluementor wrote:x != 0 means x not equal to 0.logitech wrote:
|x-3|!=0
Okay I just checked it and The factorial 0! evaluates to 1.
So this disproves my solution. I don't know what |x-3|!=0 means!
-BM-
So what is X ? if not 0 ( we know it is not ZERO )

Bluementor - thank you!Stuart Kovinsky wrote:Everyone just needs to read statement (2) as:
(2) |x - 3| is not equal to 0
In other words, all (2) tells us is that x is NOT equal to 3. x could be anything else, so (2) is insufficient.
When we combine, we know that:
(1) x = 1/3 or x = 3
(2) x can't be 3
So, together, x = 1/3, which gives us a definite YES answer ... choose (c) together sufficient, apart insufficient.
As bluementor noted, the notation "!=" is often used to stand for "not equal to" and is NOT notation that you'll ever see on the GMAT.
for statement 1: can you tell me why did you square on both sides??logitech wrote:Question can be paraphrased as:erukumk wrote:is |X| < 1?
1) |X+1|=2|X-1|
2)|X-3|!=0
Is X between -1 and + 1 ?
1) |X+1|=2|X-1|
if we take the square of both side and re-arrange it:
3X^2 - 10X + 3 = 0
X = 1/3 or X = 3
INSUF
2) IX-3|!=0
|X-3|!=0 , 0! = 0
Means that X=3
3 is not between -1 and + 1
Sufficient
Hence, B