is |x| < 1?

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Source: — Data Sufficiency |

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Re: is |x| < 1?

by jimmiejaz » Wed Nov 05, 2008 4:48 am
erukumk wrote:is |X| < 1?
1) |X+1|=2|X-1|
2)|X-3|!=0
can u post the OA pls...

Is it C?

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Re: is |x| < 1?

by 4meonly » Wed Nov 05, 2008 5:47 am
erukumk wrote: 2)|X-3|!=0
What is this?

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Re: is |x| < 1?

by jimmiejaz » Wed Nov 05, 2008 5:52 am
4meonly wrote:
erukumk wrote: 2)|X-3|!=0
What is this?
I guess it means |x-3| is not equal to 0.

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by 4meonly » Wed Nov 05, 2008 6:16 am
Thus, I think C

I saw this Q here but I cant find the link

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Re: is |x| < 1?

by logitech » Wed Nov 05, 2008 8:56 am
erukumk wrote:is |X| < 1?
1) |X+1|=2|X-1|
2)|X-3|!=0
Question can be paraphrased as:

Is X between -1 and + 1 ?

1) |X+1|=2|X-1|

if we take the square of both side and re-arrange it:

3X^2 - 10X + 3 = 0

X = 1/3 or X = 3

INSUF

2) IX-3|!=0

|X-3|!=0 , 0! = 0

Means that X=3

3 is not between -1 and + 1

Sufficient

Hence, B
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Re: is |x| < 1?

by bluementor » Wed Nov 05, 2008 9:05 am
logitech wrote: 2) IX-3|!=0

|X-3|!=0 , 0! = 0

Means that X=3

3 is not between -1 and + 1

Sufficient

Hence, B
Correct me if I'm wrong here:

|x-3|!=0 simply means x !=3. Therefore, x could lie between -1 and 1 or it could be anything else, except 3. So this statement is not sufficient.

-BM-

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Re: is |x| < 1?

by logitech » Wed Nov 05, 2008 9:18 am
bluementor wrote:
logitech wrote: 2) IX-3|!=0

|X-3|!=0 , 0! = 0

Means that X=3

3 is not between -1 and + 1

Sufficient

Hence, B
Correct me if I'm wrong here:

|x-3|!=0 simply means x !=3. Therefore, x could lie between -1 and 1 or it could be anything else, except 3. So this statement is not sufficient.

-BM-
|x-3|!=0

Okay I just checked it and The factorial 0! evaluates to 1.

So this disproves my solution. I don't know what |x-3|!=0 means! :?
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Re: is |x| < 1?

by bluementor » Wed Nov 05, 2008 11:02 am
logitech wrote:
|x-3|!=0

Okay I just checked it and The factorial 0! evaluates to 1.

So this disproves my solution. I don't know what |x-3|!=0 means! :?
x != 0 means x not equal to 0.

-BM-

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Re: is |x| < 1?

by logitech » Wed Nov 05, 2008 11:05 am
bluementor wrote:
logitech wrote:
|x-3|!=0

Okay I just checked it and The factorial 0! evaluates to 1.

So this disproves my solution. I don't know what |x-3|!=0 means! :?
x != 0 means x not equal to 0.

-BM-
it does not make any sense my friend.

So what is X ? if not 0 ( we know it is not ZERO )
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Re: is |x| < 1?

by bluementor » Wed Nov 05, 2008 11:18 am
logitech wrote:
bluementor wrote:
logitech wrote:
|x-3|!=0

Okay I just checked it and The factorial 0! evaluates to 1.

So this disproves my solution. I don't know what |x-3|!=0 means! :?
x != 0 means x not equal to 0.

-BM-
it does not make any sense my friend.

So what is X ? if not 0 ( we know it is not ZERO )
Well, we don't know what x is. All we know about x is that its not equal to 0. Thats what x != 0 means.

P.S. By the way, this x!=0 thing has nothing to do with the original problem here. I'm just using this to clearify the meaning of the != notation. You will definitely not see this type of notation being used in the real test, gmatprep or other books. It is only being used here since the proper "not equal to" sign is not easily produced with the keyboard.

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by scoobydooby » Wed Nov 05, 2008 11:30 am
|x-3|!=0
or (x-3)(x-2)(x-1)x......1=0 one of these terms must be 0
or x=0 or x=3 or x=2 ..so on. there is no definite value of x

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by Stuart@KaplanGMAT » Wed Nov 05, 2008 12:41 pm
Everyone just needs to read statement (2) as:

(2) |x - 3| is not equal to 0

In other words, all (2) tells us is that x is NOT equal to 3. x could be anything else, so (2) is insufficient.

When we combine, we know that:

(1) x = 1/3 or x = 3
(2) x can't be 3

So, together, x = 1/3, which gives us a definite YES answer ... choose (c) together sufficient, apart insufficient.

As bluementor noted, the notation "!=" is often used to stand for "not equal to" and is NOT notation that you'll ever see on the GMAT.
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by logitech » Wed Nov 05, 2008 1:06 pm
Stuart Kovinsky wrote:Everyone just needs to read statement (2) as:

(2) |x - 3| is not equal to 0

In other words, all (2) tells us is that x is NOT equal to 3. x could be anything else, so (2) is insufficient.

When we combine, we know that:

(1) x = 1/3 or x = 3
(2) x can't be 3

So, together, x = 1/3, which gives us a definite YES answer ... choose (c) together sufficient, apart insufficient.

As bluementor noted, the notation "!=" is often used to stand for "not equal to" and is NOT notation that you'll ever see on the GMAT.
Bluementor - thank you!

Thanks Stuart for making it clear.
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Re: is |x| < 1?

by erukumk » Wed Nov 05, 2008 5:11 pm
logitech wrote:
erukumk wrote:is |X| < 1?
1) |X+1|=2|X-1|
2)|X-3|!=0
Question can be paraphrased as:

Is X between -1 and + 1 ?

1) |X+1|=2|X-1|

if we take the square of both side and re-arrange it:

3X^2 - 10X + 3 = 0

X = 1/3 or X = 3

INSUF

2) IX-3|!=0

|X-3|!=0 , 0! = 0

Means that X=3

3 is not between -1 and + 1

Sufficient

Hence, B
for statement 1: can you tell me why did you square on both sides??