Would love some help with this one... Can't figure out how to use the information given to plot additional values.
Thanks!
Thanks!
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First Consider statement 1) LQPR =30; as triangle QPS and RPS are right angle triangles, therefore LQPS+LPQR=90;aleph777 wrote:Would love some help with this one... Can't figure out how to use the information given to plot additional values.
Thanks!
A very useful approach when a DS question asks for the value of an angle (or, in this case, the difference between 2 angles):

Not quite arbitrary. We need to plug in angle measurements that satisfy the rules of geometry and all the conditions given in the problem. Plugging in allows us to see how all the angles affect each other.aleph777 wrote:Mitch, in your solution, when you say plug in twice, you mean just pick arbitrary numbers to fill out your additional angles based on the first angle given in the statements?
Much easier than the solution offered in the OG12.An easy approach to Q10 in the OG12 (the star question) is to plug in for the angle measurements. We're being asked to find the sum of the angles measurements of the 5 points of the star. The key is to plug in values that follow the rules of geometry:
Let's start with the most unusual shape, the pentagon inside the star. For any polygon with n sides, the sum of the interior angles = (n-2)*180. Thus, the sum of the angles inside the pentagon = (5-2)*180 = 540. There are 5 angles inside the pentagon. To make the math easy, let's plug in 540/5 = 108 for each interior angle.
Each of the adjacent angles must be 180-108 = 72 (see the picture), because the sum of angles that form a straight line must be 180.
There are 5 triangles around the outside of the star. The sum of the angles inside each of these triangles must be 180. This forces each point of the star to be 180-72-72 = 36.
Since the star has 5 points, the sum of the angle measurements of all 5 points is 5*36 = 180.
Anurag@Gurome wrote:Statement 1: In triangle PQR,Hence, angle PRS - angle PQR = angle QPR = 30 degrees
- angle QPR + angle PQR = (180 - angle PRQ) = angle PRS
Sufficient
Statement 2: In triangle PQR,Hence, angle QPR = (180 - (angle PQR + angle PRQ)) degrees = (180 - 150) degrees = 30 degrees, i.e. we have same information as of statement 1.
- angle QPR + angle PQR + angle PRQ = 180 degrees
Sufficient
The correct answer is D.
GMATGuruNY wrote:A very useful approach when a DS question asks for the value of an angle (or, in this case, the difference between 2 angles):
Plug in twice, following the rules of geometry.
Why twice? So that we can see what happens to the value of PRS-PQR.
If the value of PRS-PQR stays the same, the statement is sufficient.
If the value of PRS-PQR changes, the statement is insufficient.
As we plug in, we have to follow the rules of geometry. If angles are inside a triangle, their sum must be 180. If angles form a straight line, their sum must be 180.
Statement 1: QPR = 30 degrees
The image above shows two combinations of angle measurements in which QPR=30. In each case, PRS-PQR=30. Since the value of PRS-PQR stays the same, sufficient.
Statement 2: PQR + PRQ = 150 degrees
The image used in Statement 1 shows two combinations of angle measurements in which PQR+PRQ =150. In each case, PRS-PQR=30. Since the value of PRS-PQR stays the same, sufficient.
The correct answer is D.
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