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Source: — Data Sufficiency |
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by Zipper » Sun Dec 07, 2008 6:08 am
Let x be the difference between the salaries of M and K.

M-x+J+x=2K
M+J=2K
K=(M+J)/2

Stmt I

J=30,000 We don't know anything about M and K //insuff

Stmt II

K=40,000 =>

M+J=80,000 =>

M+J+K=120,000 mean=40,000 //suff

Therefore, B
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by bacali » Mon Dec 08, 2008 9:00 am
Can someone explain this further. I'm still confused about the initial setup. Thanks.
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by EricLien9122 » Mon Dec 08, 2008 9:20 am
One of the equation is m-j=2m-2k. We can rewrite it as m+j=2k.

question is asking about m+j+k.

statement 1: j=30k. We can't solve the equation with j=30k, therefore insufficient.

statement 2: k=40k, we can solve m+j, which is 80k.

avg.=(40k+80k)/3=40k, therefore sufficient.
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