-
determined
- Newbie | Next Rank: 10 Posts
- Posts: 2
- Joined: Sun Nov 01, 2009 7:32 pm
Probability that student A can solve the problem=1/3
Probability that student B can solve the problem=1/5
Probability that only one of them can solve the problem=?
How would you solve this problem? I thought since they are independent events,
p(AUB)= p(A)+P(B)-p(A and B)= 1/3+1/5-1/3.1/5= 7/15
but if you try to solve it as
p(A).(1-p(B))+ p(B).(1-p(B))= 1/3.4/5 + 2/3.1/5 = 6/15
Which one is correct??
Probability that student B can solve the problem=1/5
Probability that only one of them can solve the problem=?
How would you solve this problem? I thought since they are independent events,
p(AUB)= p(A)+P(B)-p(A and B)= 1/3+1/5-1/3.1/5= 7/15
but if you try to solve it as
p(A).(1-p(B))+ p(B).(1-p(B))= 1/3.4/5 + 2/3.1/5 = 6/15
Which one is correct??
