BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

PS - divisible question

Expert replies
by ccassel » Sat Apr 02, 2011 12:39 pm
How would you explain the answer to this question? Does it have something to do with an odd prime #?

If n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is:

A. 6
B. 12
C. 24
D. 36
E. 48

Thanks,
Join the discussion
Source: — Problem Solving |

by rohu27 » Sat Apr 02, 2011 9:30 pm
a similar problem was discused few days bck on this forum. let me try this again.
n^2 is divisible by 72, so n^2=72k (k is any inetegr- n^2 is a multiple of 72)
so n=sqrt(72k)=6*sqrt(2k)
the question asks for a +ve integer tht MUST divide n,->whtevr the value of n, it shud be divisible by this integer.
now n shud be an integer,so lets see for which values of k does n become an integer,
the least value of k for which n becomes an integer is k=2, then n =12
so 12 is the iteger which divides n always.

option B.
Join the discussion

by ccassel » Sun Apr 03, 2011 8:51 am
Thanks for the answer. Can someone expand on this?

To summarize..
- n is positive
- n^2 is divisible by 72
- what is the largest positive integer that must divide n?

1. If they are asking for the "largest positive integer that must divide n"; why would we use the smallest possible (integer) value of "k" to solve the question? For example, if we used "k=8" the answer would be (c)24.

Cheers,
Join the discussion

by rohu27 » Sun Apr 03, 2011 9:09 am
important thgn to note here is the word MUST, whatevr the value of n, this integer MUST divide it.
if we take the example you mentioned, if k=8, n woild be 24.
if 24 is the largest possible integer we are looking for, how abt the below case?
k=2,n=12. remember 24 MUST divide n, but 24 doesnt divide 12.
so we are finding the min. value of n so tht if for tht value the integer divides n, rest all wud just be multiples of tht particular n.
largest positive integer, - both 6 and 12 would divide all values of n, the larger one would be 12.

hope this helps.
Join the discussion

by tpr-becky » Tue Apr 05, 2011 8:38 am
The words "divisibe by" are your clue that this is about factors.

if n^2 is divisible by 72 that means that n^2 must have all the prime factors 72

72 has 2,2,2,3,3 as it's prime factors.

since it is n^2 that has these we know that n has a 2 and a 3 (by pulling out the factor pairs) - but there is a still a 2 left and thus n must have another 2 in it (because the square is divisible and thus can't be a decimal). thus n must have 2, 2, and 3 as factors (can have many more but must have these).

Thus n is divisible by 12 - n could be divisible by the larger numbers but we don't know for sure a thus the answer is B.

Best of Luck
Becky
Master GMAT Instructor
The Princeton Review
Irvine, CA
Join the discussion