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Expert replies
by harsh.champ » Fri Feb 19, 2010 10:19 am
What is the average of a, b, and c?

1. 2a + b + 4c = 23
2. 3a + 4b + c = 22
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Source: — Data Sufficiency |

by thephoenix » Fri Feb 19, 2010 10:29 am
harsh.champ wrote:What is the average of a, b, and c?

1. 2a + b + 4c = 23
2. 3a + 4b + c = 22
1) insuff

2) insuff

1+2) 5a+5b+5c=55---->a+b+c=11--->(a+b+c)/3=11/3

hence suff
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by shashank.ism » Sun Feb 21, 2010 6:49 am
harsh.champ wrote:What is the average of a, b, and c?

1. 2a + b + 4c = 23
2. 3a + 4b + c = 22
St.1) 2a +b+4c = 23 so we don't know all the values we require atleast 2 values.....not suff...
St.2) 3a + 4b + c = 22 so we don't know all the values we require atleast 2 values.....not suff...

combined: add the two values so 5a + 5b + 5c = 45 --> a+b+c= 9 so avg 9/3 = 3----suff. Ans C
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by shashank.ism » Sun Feb 21, 2010 6:51 am
thephoenix wrote:
harsh.champ wrote:What is the average of a, b, and c?

1. 2a + b + 4c = 23
2. 3a + 4b + c = 22
1) insuff

2) insuff

1+2) 5a+5b+5c=55---->a+b+c=11--->(a+b+c)/3=11/3

hence suff
I think u have done mistake in addition in haste...
23+ 22 = 45 ....
so 5a+5b+5c=45 ....
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