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700-800 level Q...help

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by ejager » Sun Jun 07, 2015 10:46 am
If list S contains nine distinct integers, at least one of which is negative, is the median of the integers in list S positive?

(1) The product of the nine integers in list S is equal to the median of list S.

(2) The sum of all nine integers in list S is equal to the median of list S

I have the MGMAT solution but need a different way to think about it
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Source: — Data Sufficiency |

by GMATGuruNY » Sun Jun 07, 2015 11:10 am
If list S contains nine distinct integers, at least one of which is negative, is the median of the integers in list S positive?

(1) The product of the nine integers in list S is equal to the median of list S.

(2) The sum of all nine integers in list S is equal to the median of list S.
In ascending order, let the 9 distinct integers be a, b, c, d, M, e, f, g, h, where M = median.

Statement 1: The product of the nine integers in list S is equal to the median of list S.
Thus:
a*b*c*d*M*e*f*g*h = M.
If M is a nonzero integer, we can divide each side by M, with the following result:
a*b*c*d*e*f*g*h = 1.
It is not possible that the product of 8 distinct integers is equal to 1.
Implication:
M CANNOT be a nonzero integer, implying that M=0 and that the median is NOT positive.
SUFFICIENT.

Statement 2: The sum of all nine integers in list S is equal to the median of list S.
Thus:
a+b+c+d+M+e+f+g+h = M.
Subtracting M from both sides, we get:
a+b+c+d+e+f+g+h = 0.
Implication:
As long as the sum above is equal to 0, M can be ANY INTEGER VALUE.
Case 1: -4, -3, -2, -1, 0, 1, 2, 3, 4.
Here, sum = median = 0.
Case 2: -5, -4, -3, -2, 1, 2, 3, 4, 5.
Here, sum = median = 1.
Since the median is positive in Case 2 but not in Case 1, INSUFFICIENT.

The correct answer is A.
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by nikhilgmat31 » Mon Jun 08, 2015 4:58 am
Hi GMATGuruNY,

How you deduce below from Statement 1

Statement 1: The product of the nine integers in list S is equal to the median of list S.
Thus:
a*b*c*d*M*e*f*g*h = M.
If M is a nonzero integer, we can divide each side by M, with the following result:
a*b*c*d*e*f*g*h = 1.

It is not possible that the product of 8 distinct integers is equal to 1.
Implication:
M CANNOT be a nonzero integer, implying that M=0 and that the median is NOT positive.
SUFFICIENT.


it is correct that 8 integers can't be 1, so you mean to say product of all integers is 0 saying M=0 ?
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by GMATGuruNY » Mon Jun 08, 2015 6:43 am
nikhilgmat31 wrote:How you deduce below from Statement 1
Implication:
M CANNOT be a nonzero integer, implying that M=0 and that the median is NOT positive.
SUFFICIENT.
The CONTRAPOSITIVE of an if-then statement is always true.
Original statement: If A, then B.
Contrapositive: If not B, then not A.

Example:
Original statement: If John is in New York City, then John is in the United States.
Contrapositive: If John is not in the United States, then John is not in New York City.
If M is a nonzero integer, we can divide each side by M, with the following result:
a*b*c*d*e*f*g*h = 1.
Original statement: If M ≠ 0, then a*b*c*d*e*f*g*h = 1.
Contrapositive: If a*b*c*d*e*f*g*h ≠ 1, then M = 0.
Since we know that a*b*c*d*e*f*g*h ≠ 1, we can conclude that M=0.
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