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the cube root of x + y^2

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the cube root of x + y^2

by sanju09 » Fri Oct 15, 2010 10:10 pm
If x and y are positive integers, is the cube root of x + y^2 an integer?

[1] x = y^2 (y - 1).

[2] x = 2.


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by pradeepkaushal9518 » Sat Oct 16, 2010 12:17 am
x,y positive intergers , cube root of x+y^2 an integer?

1.x=y^2(y-1)

x=y^3-y^2

x+y^2=y^3-y^2+y^2=y^3 so cube root =y y is interger so suff

2.x=2

no idea about y so not suff

imo A
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