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chetanojha
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2) x^3<0 => if x^3 <0, then x has to be negative.
D.
This is what came to my mind, I am not expert
Somebody, please explain.
Thanks
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chetanojha wrote:How can we solve this.
Is x<0?
1. -2x>0
2. x^3<0
OA: D
.Odd powers of x will share the sign of x. If x is positive, then x raised to an odd power will also be positive
If x is negative, then x raised to an even power will also be negative.
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