i am not convinced with the explanation

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i am not convinced with the explanation

by sana.noor » Fri Aug 30, 2013 1:40 am
Reserve tank 1 is capable of holding z gallons of water. Water is pumped into tank 1, which starts off empty, at a rate of x gallons per minute. Tank 1 simultaneously leaks water at a rate of y gallons per minute (where x > y). The water that leaks out of tank 1 drips into tank 2, which also starts out empty. If the total capacity of tank 2 is twice the number of gallons of water actually existing in tank 1 after one minute, does tank 1 fill up before tank 2?

(1) zy < 2x2 - 4xy + 2y2

(2) The total capacity of tank 2 is less than one-half that of tank 1.

OA is A
according to explanations the capacity of tank 1 is z gallons, however question says that the capacity of reserve tank is z gallons. explanation says that capacity of tank 2 is (x-y). i mean this is totally a confusing question, i need help


Manhattan explanation:
If water is rushing into tank 1 at x gallons per minute while leaking out at y gallons per minute, the net rate of fill of tank 1 is x - y. To find the time it takes to fill tank 1, divide the capacity of tank 1 by the rate of fill: z / (x - y).


We know that the rate of fill of tank 2 is y and that the total capacity of tank 2 is twice the number of gallons remaining in tank 1 after one minute. After one minute, there are x - y gallons in tank 1, since the net fill rate is x - y gallons per minute. Thus, the total capacity of tank 2 must be 2(x - y).

The time it takes to fill tank two then is
2(x - y)/y.

The question asks us if tank 1 fills up before tank 2.

We can restate the question: Is
z/x - y < 2(x - y)/y ?

(1) SUFFICIENT: We can manipulate zy < 2x2 - 4xy + 2y2:

zy < 2x2 - 4xy + 2y2
zy < 2(x2 - 2xy + y2)
zy < 2(x - y)(x - y) (dividing by x - y is okay since x - y > 0)
zyx - y<2(x - y)
(dividing by y is okay since y > 0)

z/x - y<2(x - y)/y

This manipulation shows us that the time it takes to fill tank 1 is definitely shorter than the time it takes to fill tank 2.

(2) INSUFFICIENT: We can express this statement algebraically as: 1/2(z) > 2(x - y). We cannot use this expression to provide us meaningful information about the question.

The correct answer is A.
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by vinay1983 » Fri Aug 30, 2013 6:29 am
I could do this:

Tank 1
Let z=10 gallons
X=5 g/min
y=2g/min

So in 1 min, the tank is x-y(x>y)=3 gallons time required is 10/3

Tank 2

Capacity is 2z

time required is 2z/x-y

Question is Is (x-y)<2(x-y)

Statement 2

Contradicts info given in prompt So N.S

Statement 1

zy<(2x^2)-4xy+2y^2
zy<2(x^2-2xy+y^2)
zy<2(x-y)^2

This is where I got stuck.Please help!
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by Brent@GMATPrepNow » Fri Aug 30, 2013 7:01 am
sana.noor wrote:Reserve tank 1 is capable of holding z gallons of water. Water is pumped into tank 1, which starts off empty, at a rate of x gallons per minute. Tank 1 simultaneously leaks water at a rate of y gallons per minute (where x > y). The water that leaks out of tank 1 drips into tank 2, which also starts out empty. If the total capacity of tank 2 is twice the number of gallons of water actually existing in tank 1 after one minute, does tank 1 fill up before tank 2?

(1) zy < 2x² - 4xy + 2y²

(2) The total capacity of tank 2 is less than one-half that of tank 1.

Target question: Does tank 1 fill up before tank 2?

Let's sort out the given information before we check out the statements.

Water enters tank 1 at x gallons per minute. At the same time, and water leaks out of tank 1 at y gallons per minute.
So, the net RATE of flow into tank 1 is x-y gallons per minute.
Also, the RATE of flow into tank 2 is y gallons per minute.

What about capacities?
We're told that the total capacity of tank 2 is twice the number of gallons of water actually existing in tank 1 after one minute
Well, after 1 minute, there are x-y gallons in tank 1.
So, the CAPACITY of tank 2 is 2(x-y) gallons.
Also, we're told that the CAPACITY of tank 1 is z gallons.

The target question asks, "Does tank 1 fill up before tank 2?".
In other words, "Is the time to fill tank 1 less than the time to fill up tank 2?".

IMPORTANT: Time to fill a tank = (capacity)/(rate of flow into tank)
When we plug CAPACITIES and flow RATES into the target question, we get . . .

Rephrased target question: "Is z/(x-y) < 2(x-y)/y?"

Finally, we can clean up this inequality by multiplying both sides by (x-y) and by y to get. . .
Rephrased target question: Is zy < 2(x-y)(x-y) ?

Okay, now onto the statements.

Statement 1: zy < 2x² - 4xy + 2y²
If we factor the right side of this inequality, it tells us that zy < 2(x-y)(x-y)
Perfect! This tells us exactly what we need to know.
Since we can answer the rephrased target question with certainty, statement 1 is SUFFICIENT

Statement 2: The total capacity of tank 2 is less than one-half that of tank 1.
The CAPACITY of tank 1 is z gallons. The CAPACITY of tank 2 is 2(x-y) gallons.
So, statement 2 tells us that 2(x-y) < (1/2)z
Multiply both sides by 2 to get 4(x-y) < z
Is this enough information to determine whether or not zy < 2(x-y)(x-y)? It's hard to tell.
The solution you cited just says "We cannot use this expression to provide us meaningful information about the question."
I suppose this is true, in which case we might conclude that statement 2 is NOT SUFFICIENT.
However, if you're not 100% convinced by this, you may want to convince yourself by finding values of x, y and z that satisfy statement 2, yet yield conflicting answers to the target question (which could waste valuable time). Nevertheless, let's try it.

Case a: x=2, y=1 and z=5, in which case zy > 2(x-y)(x-y)
Case b: x=11, y=1 and z=50, in which case zy < 2(x-y)(x-y)
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

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by GMATGuruNY » Fri Aug 30, 2013 10:37 am
sana.noor wrote:Reserve tank 1 is capable of holding z gallons of water. Water is pumped into tank 1, which starts off empty, at a rate of x gallons per minute. Tank 1 simultaneously leaks water at a rate of y gallons per minute (where x > y). The water that leaks out of tank 1 drips into tank 2, which also starts out empty. If the total capacity of tank 2 is twice the number of gallons of water actually existing in tank 1 after one minute, does tank 1 fill up before tank 2?

(1) zy < 2x2 - 4xy + 2y2

(2) The total capacity of tank 2 is less than one-half that of tank 1.

OA is A
Statement 1: zy < 2x² - 4xy + 2y².
To see the implications of this inequality, plug in values for x and y and solve for z.
Let x=10 and y=2.
Then:
z(2) < 2(10²) - 4(10)(2) + 2(2²)
2z < 128
z < 64.
Here, the capacity of tank 1 is LESS than 64 gallons.

Tank 1:
Since tank 1 receives x=10 gallons per minute and loses y=2 gallons per minute, the net gain for tank 1 = 10-2 = 8 gallons per minute.
Since the capacity of tank 1 is LESS than 64 gallons, the time to fill tank 1 at a rate of 8 gallons per minute must be LESS than 64/8 = 8 minutes.

Tank 2:
After one minute, the volume in tank 1 = 8 gallons.
Since the capacity of tank 2 is twice the volume in tank 1 after one minute, the capacity of tank 2 = 2*8 = 16 gallons.
Time to fill tank 2 at a rate of y=2 gallons per minute = 16/2 = 8 minutes.

While tank 1 requires LESS than 8 minutes, tank 2 requires EXACTLY 8 minutes.
The case above illustrates that tank 1 will fill up before tank 2.
SUFFICIENT.

Statement 2: The total capacity of tank 2 is less than one-half that of tank 1.
In statement 1 above, it is possible that the capacity of tank 2 = 16 gallons, while the capacity of tank 1 = 63 gallons.
These values also satisfy statement 2.
As we saw above, the result will be that tank 1 fills up before tank 2.
But if we increase the capacity of tank 1 to 1000 gallons and leave all of the other values the same, tank 2 will fill up before tank 1.
INSUFFICIENT.

The correct answer is A.
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by \'manpreet singh » Sat Aug 31, 2013 4:26 am
Very good question, and Mitch i think your method of plugging values would work FASTEST in such question :).

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by \'manpreet singh » Sat Aug 31, 2013 4:27 am
Very good question, and Mitch i think your method of plugging values would work FASTEST in such question :).