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Logitech DS1
Source: Beat The GMAT — Data Sufficiency |
-
jackcrystal
- Senior | Next Rank: 100 Posts
- Posts: 31
- Thanked: 1 times
10 employees, 2 women have to be selected. i.e. p
is p>1/2 ?
Statement I
More than half employees are women.
if women=6
probability = 6/10 * 5/10 = 1/3 < 1/2
If women=9
probability = 9/10*8/9 = 4/5 > 1/2
Insufficient.
Statement II
Probability that both employees are men is less 1/10
lets take 1/10
probability of both women = 1-1/10 = 9/10 > 1/2
if probability of men can be anything less than 1/10 the probability of women will increase. 1/10 is satisfying our question stem, therefore every number less than 1/10 will satisfy the question stem. Sufficient.
Hence B
is p>1/2 ?
Statement I
More than half employees are women.
if women=6
probability = 6/10 * 5/10 = 1/3 < 1/2
If women=9
probability = 9/10*8/9 = 4/5 > 1/2
Insufficient.
Statement II
Probability that both employees are men is less 1/10
lets take 1/10
probability of both women = 1-1/10 = 9/10 > 1/2
if probability of men can be anything less than 1/10 the probability of women will increase. 1/10 is satisfying our question stem, therefore every number less than 1/10 will satisfy the question stem. Sufficient.
Hence B
Last edited by parallel_chase on Sat Nov 08, 2008 12:07 am, edited 1 time in total.
No rest for the Wicked....
You da man!!parallel_chase wrote:10 employees, 2 women have to be selected. i.e. p
is p>1/2 ?
Statement I
More than half employees are women.
if women=6
probability = 6/10 * 5/10 = 1/3 < 1/2
If women=9
probability = 9/10*8/9 = 4/5 > 1/2
Insufficient.
Statement II
Probability that both employees are men is less 1/10
lets take 1/10
probability of both women = 1-1/10 = 9/10 > 1/2
if probability of men can be anything less than 1/10 the probability of women will increase. 1/10 is satisfying our question stem, therefore every number less than 1/10 will satisfy the question stem. Sufficient.
Hence B
Let me know if you still have any doubts.
Joined: 20 Jun 2007
Posts: 912
Will you ever take the test or you just like to hang out here ?
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
logitech wrote: You da man!!
Joined: 20 Jun 2007
Posts: 912
Will you ever take the test or you just like to hang out here ?
My Test is scheduled for tomorrow
1:15 PM third attempt.Yeah I jonied this beautiful forum on 20th June 2007 during my first attempt. After my first two attempts i dint study for more than a year because of work.
Lets hope this will be my last time. When are you taking the test.
No rest for the Wicked....
TOMORROW!!!!!!!!!!!!!!!parallel_chase wrote:logitech wrote: You da man!!
Joined: 20 Jun 2007
Posts: 912
Will you ever take the test or you just like to hang out here ?
My Test is scheduled for tomorrow
Yeah I jonied this beautiful forum on 20th June 2007 during my first attempt. After my first two attempts i dint study for more than a year because of work.
Lets hope this will be my last time. When are you taking the test.
Well I live in California, I am not sure what time it is over where you live but...FUCK IT MAN!! GO GET SOME REST!!
KICK SOME ASS TOMORROW!!!
I want to see you for the last time in this forum in couple of days when you are telling us how you BEAT it this time.
Good luck comrade!
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
parallel,parallel_chase wrote:10 employees, 2 women have to be selected. i.e.
Statement II
Probability that both employees are men is less 1/10
lets take 1/10
probability of both women = 1-1/10 = 9/10 > 1/2
if probability of men can be anything less than 1/10 the probability of women will increase. 1/10 is satisfying our question stem, therefore every number less than 1/10 will satisfy the question stem. Sufficient.
Hence B
have a doubt: if p(both men)=1/10 then would 9/10 not represent p(not both men? which will include 1 man, 1 woman or both women. if P(one woman, 1 man )=9/10, can we infer p(both women)>1/2?
You are absolutely right. This is exactly what I hate about myself.scoobydooby wrote: parallel,
have a doubt: if p(both men)=1/10 then would 9/10 not represent p(not both men? which will include 1 man, 1 woman or both women. if P(one woman, 1 man )=9/10, can we infer p(both women)>1/2?
Nice Spot.
answer cannot be B.
Thanks.
No rest for the Wicked....
you will do very well, all the best for tomorrowparallel_chase wrote:You are absolutely right. This is exactly what I hate about myself.scoobydooby wrote: parallel,
have a doubt: if p(both men)=1/10 then would 9/10 not represent p(not both men? which will include 1 man, 1 woman or both women. if P(one woman, 1 man )=9/10, can we infer p(both women)>1/2?
Nice Spot.
answer cannot be B.
Thanks.
Interesting question.
let's say there are x women and y men.
x+ y =10 -------------------(1)
Now 2 people out of 10 can be selected 2C10 ways.
2 women from x women can be selected 2Cx ways.
Therefore, the probability of selecting both women
P(W)=(2Cx)/(2C10)=x*(x-1)/90 ------------------(2)
x =6, 7, 8, 9 Therefore, P(W) can be .33, .46, .62, .8
(A) is NOT SUFFICIENT
Probability of selecting both men P(M)= y*(y-1)/90 ------(3)
y*(y-1)/90 < 1/10
OR y(y-1) <9 ------------------- (3)
Therefore, y = either 2 or 3 (there should be at least 2 men)
Therefore there are either 7 or 8 women.
We have seen that when for 7 or 8 women, P(W) is can be less than (.46) or greater than 0.5 (.62)
Therefore, (B) is NOT SUFFICIENT.
Together we get no additional info.
Therefore (E)
let's say there are x women and y men.
x+ y =10 -------------------(1)
Now 2 people out of 10 can be selected 2C10 ways.
2 women from x women can be selected 2Cx ways.
Therefore, the probability of selecting both women
P(W)=(2Cx)/(2C10)=x*(x-1)/90 ------------------(2)
x =6, 7, 8, 9 Therefore, P(W) can be .33, .46, .62, .8
(A) is NOT SUFFICIENT
Probability of selecting both men P(M)= y*(y-1)/90 ------(3)
y*(y-1)/90 < 1/10
OR y(y-1) <9 ------------------- (3)
Therefore, y = either 2 or 3 (there should be at least 2 men)
Therefore there are either 7 or 8 women.
We have seen that when for 7 or 8 women, P(W) is can be less than (.46) or greater than 0.5 (.62)
Therefore, (B) is NOT SUFFICIENT.
Together we get no additional info.
Therefore (E)
Drill baby drill !
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GMATPowerPrep Test1= 740
GMATPowerPrep Test2= 760
Kaplan Diagnostic Test= 700
Kaplan Test1=600
Kalplan Test2=670
Kalplan Test3=570
