1
Let the actual distance he traveled be d
Let the actual speed be s
Let the actual time be t

d=st.......(1)

Now from 1st condition,
if speed was s+10, time was t+1 then distance he traveled would have been d+70
As per formula we can write this as

d+70=(s+10)(t+1) (Distance=Speed*Time)
Solving we get

5t+s=65........(2)

from condition 2
if speed was s+10, time was t+2, then how much more distance would he have covered than he actually did. Actual distance covered is d. So let the additional distance covered be x. Hence, total distance covered is d+x.

d+x=(s+10)(t+2) (Distance=Speed*Time)
Solving we get,
x-20=10t+2s
x-20=2(5t+s)
x-20=2(65) from (2)
x=150 hence D