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HELP TRAINGLES AND CIRCLES!!!

Expert replies
Source: — Problem Solving |

by gmat740 » Mon Apr 13, 2009 7:44 pm
circle S

2r = l
r = l/2

so Area, A = pi*(l/2)^2

A = pi* (l^2)/4

Circle T

2r = Sqrt(2)*l [ because length of diagonal is sqrt(2)*l]

so r = l/sqrt(2)

Area, A= pi* (l^2)/2

= 2*(Area of S)

Hope this helps

karan
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