For the equation a^x/a^y=a^-10 and (a^y)^3=a^-x, if a>1 what is the value of x
A)2.5
B)-7.5
C)2
D)1
A)2.5
B)-7.5
C)2
D)1
Given: a^x/a^y = a^(-10)Hmna wrote:For the equation a^x/a^y = a^-10 and (a^y)^3 = a^-x, if a>1 what is the value of x
A)2.5
B)-7.5
C)2
D)1
Simplify: a^(x-y) = a^(-10)
So, we can conclude that x-y = -10
Given: (a^y)^3 = a^-x
Simplify: a^(3y) = a^(-x)
So, we can conclude that 3y = -x
We have two equations:
x-y = -10
3y = -x
Take x-y = -10 and solve for y to get: y = x + 10
Now take 3y = -x and replace y with x + 10 to get: 3(x + 10) = -x
Expand: 3x + 30 = -x
Subtract 3x from both sides: 30 = -4x
Solve: x = -7.5
Answer: B
