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by chaitanya.mehrotra » Thu Jul 28, 2011 8:09 am
Greg, Marcia, Peter, Jan, Bobby, and Cindy go to a movie and sit next to each
other in 6 adjacent seats in the front row of the theater. If Marcia and Jan
will not sit next to each other, in how many different arrangements can the
six people sit?
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by [email protected] » Thu Jul 28, 2011 8:50 am
6! - (10*4!)
=5!(6-2)
=5!*4 = 480

Is it correct?
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by Freakinout » Mon Aug 01, 2011 11:00 pm
My Solution:

Total ways of arranging 6 people = 6 ! = 720

2 people never come together = Total - P(Always come together)

P(Always come together):

[MJ]GMPB
5!*2 = 240


Total - P(Always come together) = 720 -240 = 480 ( i think its correct)
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