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by hpgmat » Mon Dec 14, 2009 2:45 pm
If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x?
y/200
2y
50y
50/y
5000/y

i get D as an answer , but the correct answer is E.

could some one explain please
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by truplayer256 » Mon Dec 14, 2009 3:36 pm
m/100*2y=x-->m/x=100/2y

We want:

x*p/100=m

Solve for p:

100m/x=p

Convert P in terms of y:

100(100/2y)=5000/y
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by Scott@TargetTestPrep » Wed Dec 13, 2017 12:58 pm
hpgmat wrote:If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x?
y/200
2y
50y
50/y
5000/y

We are given that x is m percent of 2y. Thus:

x = (m/100)(2y)

We need to determine m as a percentage of x, i.e., (m/x)(100).

Let's simplify our equation:

x = (m/100)(2y)

x = 2ym/100

100x = 2ym

100/2y = m/x

50/y = m/x

Thus, (m/x)(100) = (50/y)(100) = 5000/y

Answer: E

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