BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

rate

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 117
Joined: Mon Oct 27, 2008 5:08 pm
Thanked: 1 times

rate

by [email protected] » Thu Dec 11, 2008 8:23 pm
A hiker walked for two days. On the second day the hiker walked 2 hours longer and at an average speed 1 mile per hour faster than he walked on the first day. If during the two days he walked a total of 64 miles and spent a total of 18 hours walking, what was his average speed on the first day?
(A) 2 mph
(B) 3 mph
(C) 4 mph
(D) 5 mph
(E) 6 mph

B
Top
Source: — Problem Solving |
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Mon Dec 08, 2008 7:01 am
Location: Thailand
Thanked: 1 times

by weena82 » Thu Dec 11, 2008 8:54 pm
Hi,

Hope this help

First day: walk x miles spend h hours
Average x/h mph

Second day: walk y miles spend h+2 hours
Average y/(h+2) which equals (x+h)/h

From stem we’ve got; x+y = 64 and 2h+2 = 18

Now you can solve equation to get x and h and, of course, x/h, which equals 24/8 = 3 mph.
Top
Post new topic Post Reply
• Page 1 of 1