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Sum of Cube

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Source: — Problem Solving |

by gauravgundal » Tue May 05, 2009 3:31 am
Answer : D

Sum of cube of first n natural numbers = [n^2*(n+1)^2]/4
n=20
Last edited by gauravgundal on Tue May 05, 2009 3:52 am, edited 1 time in total.
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by deepoe » Tue May 05, 2009 3:37 am
what did you filled in for N?
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