tree branches

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tree branches

by smodak » Fri Jun 24, 2011 11:29 am
Kim finds a 1-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and removes one piece of every distinct length. What fraction of the original branch remains?

A) 2/5
B) 7/15
C) 1/2
D) 8/15
E) 3/5

OA: E

Please explain your answer.
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by pemdas » Fri Jun 24, 2011 12:03 pm
you need to produce ascending array for all the markings:
1/3, 2/3, 1
1/5, 2/5, 3/5, 4/5, 1
________________________
multiply everything by 5 and 3 (alowing LCM 15):
5,10,15
3,6,9,12,15 ---> 3,5,6,9,10,12,15 (remember we have common denominator of 15)
_________________________
now we get pieces of distinct sizes (distance between markings)
{3,2,1,3,1,2,3) and we get all repeats in 3,2 and 1, So we subtract 6 and get (15-6)/15 or 3/5


smodak wrote:Kim finds a 1-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and removes one piece of every distinct length. What fraction of the original branch remains?

A) 2/5
B) 7/15
C) 1/2
D) 8/15
E) 3/5

OA: E

Please explain your answer.
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by GMATGuruNY » Fri Jun 24, 2011 3:49 pm
smodak wrote:Kim finds a 1-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and removes one piece of every distinct length. What fraction of the original branch remains?

A) 2/5
B) 7/15
C) 1/2
D) 8/15
E) 3/5

OA: E

Please explain your answer.
Since the question asks for a fraction, the length of the branch can be any value.
Let branch = 15.
Divided into thirds and fifths, we get:
Image
Distinct lengths are 1, 2 and 3.
Total - distinct lengths = 15-1-2-3 = 9.
Remaining length/Total = 9/15 = 3/5.

The correct answer is E.
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