I have solved it using Factor theorem.jsl wrote:What is the value of b if 2x-1 is a factor of 2x^2 + bx + 3
A. -7
B. -3
C. -1
D. 3
E. 7
2x-1 = 0
x=1/2
2* 1/4 + b/2 +3 = 0
1/2 + 3 + b/2 = 0
7/2 + b/2 = 0
therefore, b should be -7.
Whats the OA?
hard PS factors
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parallel_chase
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2x-1 = 0
x=1/2
2* 1/4 + b/2 +3 = 0
1/2 + 3 + b/2 = 0
7/2 + b/2 = 0
therefore, b should be -7.
Whats the OA?
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sudhir3127
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jsl wrote:What is the value of b if 2x-1 is a factor of 2x^2 + bx + 3
A. -7
B. -3
C. -1
D. 3
E. 7
try to factor out 2x^2 + bx + 3
we know one factor is 2X-1
( 2x-1 ) ( x-3)
2X^2- 7X +3
so we know b would be -7
I'm not even familiar with factor theorem, could you explain how it fits in here? Thank youparallel_chase wrote:I have solved it using Factor theorem.jsl wrote:What is the value of b if 2x-1 is a factor of 2x^2 + bx + 3
A. -7
B. -3
C. -1
D. 3
E. 7
2x-1 = 0
x=1/2
2* 1/4 + b/2 +3 = 0
1/2 + 3 + b/2 = 0
7/2 + b/2 = 0
therefore, b should be -7.
Whats the OA?
-
Rezinka
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- Joined: Fri Oct 15, 2010 2:39 am
- Location: New Delhi, India
- Thanked: 11 times
@ boysangur :
Whenever any expression 'a' is a factor of expression 'b', you can equate expression 'a' to 0 and put the value in expression 'b' and the result would be 0.
E.g.
Say, x-1 is a factor of a*(x^2) + b*x + c
Now,
equate x - 1 to 0
i.e.
x-1=0
or, x=1
Put this value in the given expression and the result should be 0.
i.e.
Put x = 1 in a*(x^2) + b*x + c and equate to 0.
or,
a*(1^2) + b*1 + c = 0
or, a + b + c = 0
If the valus of any 2 variables are given, we can find the value of the third.
Coming to the question that is stated :
we are given
2x - 1 is a factor of 2x^2 + bx + 3
Equate 2x-1 to 0
or, 2x - 1 = 0
or, x = 1/2
Now put this valus of x in the expression;
2*{(1/2)^2)} + b*(1/2) + 3 = 0
or, 2*(1/4) + b/2 + 3 = 0
or; 1/2 + b/2 = -3
or, b = -7
Whenever any expression 'a' is a factor of expression 'b', you can equate expression 'a' to 0 and put the value in expression 'b' and the result would be 0.
E.g.
Say, x-1 is a factor of a*(x^2) + b*x + c
Now,
equate x - 1 to 0
i.e.
x-1=0
or, x=1
Put this value in the given expression and the result should be 0.
i.e.
Put x = 1 in a*(x^2) + b*x + c and equate to 0.
or,
a*(1^2) + b*1 + c = 0
or, a + b + c = 0
If the valus of any 2 variables are given, we can find the value of the third.
Coming to the question that is stated :
we are given
2x - 1 is a factor of 2x^2 + bx + 3
Equate 2x-1 to 0
or, 2x - 1 = 0
or, x = 1/2
Now put this valus of x in the expression;
2*{(1/2)^2)} + b*(1/2) + 3 = 0
or, 2*(1/4) + b/2 + 3 = 0
or; 1/2 + b/2 = -3
or, b = -7
