3^(4n+2) +k = 9^(2n+1) + kAbdulla wrote:If n and k are positive integers, what is the remainder when 3^(4n+2) +k is divided by 10 ?
(1) k=1
(2) n=5
2n+1 is an odd number and for odd numbers, 9^(2n+1) has 9 in its unit digit. 9, 729, ..etc
st1) k =1 than the 9^(2n+1) + k will end with 0 and the remainder will be 0 when divided by 10 - SUF
st2) no info for K - INSUF
choose A
