Is 1/P > R/(R²+2)?
1). P=R
2). R>0
OA is C.
While I choose A.
first, we can dedrive from the inequality above :
1/P > R/(R²+2)=>R²+2>R*P
accoding to 1), the new inequality could be R²+2>R², sufficient
2). not sufficient.
Any comment?
1). P=R
2). R>0
OA is C.
While I choose A.
first, we can dedrive from the inequality above :
1/P > R/(R²+2)=>R²+2>R*P
accoding to 1), the new inequality could be R²+2>R², sufficient
2). not sufficient.
Any comment?
















