Q. If g(x)= 3x+√x, what is the value of g(d^2+6d+9)
Ans. Can I solve this way?
d^2+6d+9= (d+3)(d+3)= d= -3
g(-3)= 3(-3)+√-3= -9-√3.
Ans. Can I solve this way?
d^2+6d+9= (d+3)(d+3)= d= -3
g(-3)= 3(-3)+√-3= -9-√3.












