Combinations Question

This topic has expert replies
Source: — Problem Solving |

Senior | Next Rank: 100 Posts
Posts: 44
Joined: Sun Feb 15, 2009 7:37 pm
Thanked: 3 times
Followed by:1 members

by Bidisha_800 » Sun Feb 22, 2009 1:38 pm
=9*8*7*6*5!/5!*4!

=9*8*7*6/4*3*2

=18*7

=126
GMATPowerPrep Test1= 740
GMATPowerPrep Test2= 760
Kaplan Diagnostic Test= 700
Kaplan Test1=600
Kalplan Test2=670
Kalplan Test3=570

Junior | Next Rank: 30 Posts
Posts: 26
Joined: Thu Jan 15, 2009 10:25 am

by Nole23 » Sun Feb 22, 2009 3:50 pm
Could you elaborate on your math a little bit?

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Sun Feb 22, 2009 4:16 pm
To evaluate mCr, write the first r values of m! in the numerator and r! in the deniminator.

Eg: 6C2 = (6x5)/2!
Eg: 8C3=(8x7x6)/3!
Eg: 10C4 = (10x9x8x7)/4!

To evaluate these, do not calculate the products in the numerator and denominator and then simply. Rather, simplify before multiplying.

Eg: 9C3 = (9x8x7)/3! = (9x8x7)/(3x2x1)
We have 9 in the numerator and 3 in the denominator. Simply to get: (3x8x7)/(1x2x1)
Similarly, we have 8 in the numerator and 2 in the denominator. Simply to get: (3x4x7)/(1x1x1) = 84

Hope that helps.
Brent Hanneson - Creator of GMATPrepNow.com
Image