BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Division Division Division

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 487
Joined: Fri Mar 27, 2009 5:49 am
Thanked: 36 times

Division Division Division

by dtweah » Thu May 14, 2009 3:48 pm
Let N denote the smallest positive integer that satisfies the two conditions:
(i) If N is divided by 11 then the remainder is 9
(ii) If N is divided by 7 then the remainder is 5.
The sum of the digits of N is

(a) 10
(b) 11
(c) 12
(d) 13
(e) 14
Top
Source: — Problem Solving |
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Thu May 14, 2009 3:59 pm
C 12

75

So the numbers would be 75+77k wherek=0,1,2,3,4....

I had to check 11's multiples and add 9 and check. It dint take me too long though.

There might be an easier way

Regards,
CR
Top
Master | Next Rank: 500 Posts
Posts: 152
Joined: Wed Mar 12, 2008 4:36 pm
Thanked: 8 times
Followed by:2 members

by artistocrat » Thu May 14, 2009 8:25 pm
I solved this the old fashioned way, but what is an easier method than setting up a list of numbers that satisfies both conditions?
Top
Master | Next Rank: 500 Posts
Posts: 238
Joined: Tue Feb 10, 2009 8:44 am
Thanked: 9 times

by avenus » Fri May 15, 2009 2:53 am
artistocrat wrote:I solved this the old fashioned way, but what is an easier method than setting up a list of numbers that satisfies both conditions?
Maybe this:

11m + 9 = 7p + 5. This is what we're told. Add 2 to both sides of the equation:
11m + 11 = 7p + 7
11(m+1) = 7(p+1)
So
m+1 = 7, p+1 = 11
m = 6, p = 10
Top
Post new topic Post Reply
• Page 1 of 1