If a>b, is ab<b^2?
1) a<0
2) b<0
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If a>b, is ab<b^2?
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- Max@Math Revolution
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given a>b which is a-b>0
simplify the question ab<b^2 --> ab-b^2<0
b(a-b)<0 since a-b>0 is positive, we only need to check is b<0?
statement 2 is sufficient so answer is B
simplify the question ab<b^2 --> ab-b^2<0
b(a-b)<0 since a-b>0 is positive, we only need to check is b<0?
statement 2 is sufficient so answer is B
- manu.sharma
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I put in negative decimal and integer value and sometimes ab<b^2 was true and sometimes false on both the statements.
Answer should be E
Answer should be E