Algebraic approachhumpback wrote:if w,y,z are positive numbers and 2x=3y=4z, then the value of x+y+z is how many times the value of x
If 2x=3y, then y = (2/3)x
If 2x=4z, then z = (1/2)x
So, x+y+z = x + (2/3)x + (1/2)x
= (6/6)x + (4/6)x + (3/6)x
= (13/6)x
The question asks, "The value of x+y+z is how many times the value of x?"
As you can see, x+y+z is 13/6 times the value of x.
Cheers,
Brent
