# operation ?

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candygal79: Senior | Next Rank: 100 Posts; Posts: 49; Joined: Mon Feb 10, 2014 1:18 amFollowed by: 3 members

by candygal79 » Mon Mar 24, 2014 3:40 am

If the operation # is defined for all x and y by the equation x#y=2(x2yâˆ’y2x), then (6#5)/(5#6)=

a = -2

b= -1

c= 1/2

d= 2

e= 1

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Source: Beat The GMAT — Problem Solving | Mon Mar 24, 2014 3:40 am

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Brent@GMATPrepNow: GMAT Instructor; Posts: 16207; Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members; Location: Vancouver, BC; Thanked: 5254 times; GMAT Score:770

by Brent@GMATPrepNow » Mon Mar 24, 2014 4:51 am

candygal79 wrote:If the operation # is defined for all x and y by the equation x#y=2(x2yâˆ’y2x), then (6#5)/(5#6)=

a = -2

b= -1

c= 1/2

d= 2

e= 1

It's hard to tell whether or not you intended for there to be exponents here.
Use the "^" symbol to denote powers.

So, does x#y = 2^(yx^2 âˆ’ xy^2) or does x#y = 2(yx^2 âˆ’ xy^2)?

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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