BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Which of the following inequalities...

Expert replies

by BlindVision » Tue Jun 16, 2009 3:21 pm
Can someone please explain another approach to this problem? I haven't encountered this kind of question before. Thanks!
Life is a Test
Join the discussion

by arora007 » Sun Feb 20, 2011 3:58 am
maihuna wrote:
mals24 wrote:A, B & C all have infinite length

D 2<|x|<5

This option will give you 2 line segments of finite lengths

-2>-x>-5
2<[/u
]x<5


E 2<3x+4<6
This is the only option which will give you a single line of finite length. Just solve for x.

-2/3<x<2/3.

Hence the line is made of points that lie between -2/3 and 2/3.

Hope this helps.


HiMals,
to so;lve the inequality:
2<= |x| <=5

two steps:
|x| >=2 => x>= 2 or x<= -2
for |x|<=5 -5<x<5

So three lines two with infinite and one wit finite length will result.


OA is definitely E.

However I do not agree what you write for D.

I believe for D, shall be 2 line segments
a)-5 to -2 and
b)2 to 5
since x would be defined as the intersection of the lines( x<=-2 and x>=2 )AND (the line segment -5 to 5 )
https://www.skiponemeal.org/
https://twitter.com/skiponemeal
Few things are impossible to diligence & skill.Great works are performed not by strength,but by perseverance

pm me if you find junk/spam/abusive language, Lets keep our community clean!!
Join the discussion

by beatthebeast » Fri Nov 22, 2013 5:01 am
Hi guys,

could someone please explain me how to get to the two line segments in D? i have now clue how to solve the inequality with the absolute value in this problem.

Thanks a lot!
Join the discussion

by theCodeToGMAT » Fri Nov 22, 2013 7:10 am
beatthebeast wrote:Hi guys,

could someone please explain me how to get to the two line segments in D? i have now clue how to solve the inequality with the absolute value in this problem.

Thanks a lot!
Answer {E}
Attachments
solution.JPG
R A H U L
Join the discussion