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Which of the following inequalities...

Expert replies

by BlindVision » Tue Jun 16, 2009 3:21 pm
Can someone please explain another approach to this problem? I haven't encountered this kind of question before. Thanks!
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by arora007 » Sun Feb 20, 2011 3:58 am
maihuna wrote:
mals24 wrote:A, B & C all have infinite length

D 2<|x|<5

This option will give you 2 line segments of finite lengths

-2>-x>-5
2<[/u
]x<5


E 2<3x+4<6
This is the only option which will give you a single line of finite length. Just solve for x.

-2/3<x<2/3.

Hence the line is made of points that lie between -2/3 and 2/3.

Hope this helps.


HiMals,
to so;lve the inequality:
2<= |x| <=5

two steps:
|x| >=2 => x>= 2 or x<= -2
for |x|<=5 -5<x<5

So three lines two with infinite and one wit finite length will result.


OA is definitely E.

However I do not agree what you write for D.

I believe for D, shall be 2 line segments
a)-5 to -2 and
b)2 to 5
since x would be defined as the intersection of the lines( x<=-2 and x>=2 )AND (the line segment -5 to 5 )
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by beatthebeast » Fri Nov 22, 2013 5:01 am
Hi guys,

could someone please explain me how to get to the two line segments in D? i have now clue how to solve the inequality with the absolute value in this problem.

Thanks a lot!
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by theCodeToGMAT » Fri Nov 22, 2013 7:10 am
beatthebeast wrote:Hi guys,

could someone please explain me how to get to the two line segments in D? i have now clue how to solve the inequality with the absolute value in this problem.

Thanks a lot!
Answer {E}
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