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At a certain committee meeting only associate professors and

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At a certain committee meeting only associate professors and

by swerve » Sun Nov 24, 2019 3:29 am
At a certain committee meeting, only associate professors and assistant professors are present. Each associate professor has bought 2 pencils and 1 chart for the meeting, while each assistant professor bought 1 pencil and 2 charts. If a total of 10 pencils and 11 charts have been bought for the meeting, how many people are present?

A. 6
B. 7
C. 8
D. 9
E. 10

The OA is B

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by Brent@GMATPrepNow » Sun Nov 24, 2019 6:30 am
swerve wrote:At a certain committee meeting, only associate professors and assistant professors are present. Each associate professor has bought 2 pencils and 1 chart for the meeting, while each assistant professor bought 1 pencil and 2 charts. If a total of 10 pencils and 11 charts have been bought for the meeting, how many people are present?

A. 6
B. 7
C. 8
D. 9
E. 10
Notice that the question asks us to find that TOTAL number of people present.
In other words, the question does NOT ask us to find the number of associate professors or assistant professors present.

Since each person brings THREE items, and since total of 21 items were brought (10 pencils and 11 charts), then the number of people = 21/3 = 7

Answer: B

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by Scott@TargetTestPrep » Thu Nov 28, 2019 4:23 pm
swerve wrote:At a certain committee meeting, only associate professors and assistant professors are present. Each associate professor has bought 2 pencils and 1 chart for the meeting, while each assistant professor bought 1 pencil and 2 charts. If a total of 10 pencils and 11 charts have been bought for the meeting, how many people are present?

A. 6
B. 7
C. 8
D. 9
E. 10

The OA is B

Source: GMAT Prep
We can let the number of associate professors = a and the number of assistant professors = n and create two equations:

Pencil equation:

2a + n = 10

Chart equation:

a + 2n = 11

Let's add the two equations together:

3a + 3n = 21

a + n = 7

Thus, there are 7 people at the meeting.

Answer: B

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