The thin conveyor belt

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didieravoaka: Master | Next Rank: 500 Posts; Posts: 163; Joined: Tue Jan 13, 2015 11:44 am; Thanked: 2 times

by didieravoaka » Mon Nov 16, 2015 8:01 pm

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Please could you help me out with this problem?

Thank you.

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Source: Beat The GMAT — Problem Solving | Mon Nov 16, 2015 8:01 pm

GMATGuruNY: GMAT Instructor; Posts: 15539; Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members; Location: New York, NY; Thanked: 13060 times; GMAT Score:790

by GMATGuruNY » Mon Nov 16, 2015 8:22 pm

Last edited by GMATGuruNY on Mon Nov 16, 2015 8:28 pm, edited 1 time in total.

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didieravoaka: Master | Next Rank: 500 Posts; Posts: 163; Joined: Tue Jan 13, 2015 11:44 am; Thanked: 2 times

by didieravoaka » Mon Nov 16, 2015 8:57 pm

GMATGuruNY wrote:

Thank you Mitch, this is very helpful.
But I still have two questions:
1. Why the belt isn't equal to A+B+C instead of A+B+C+D since C=D?
2. Why C is not equal to 15-pi. Then C would be the answer. Meaning that it represents the distance between the centers.

Why this is not the case?

Thanks.

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jain2016: Master | Next Rank: 500 Posts; Posts: 313; Joined: Tue Oct 13, 2015 7:01 am; Thanked: 2 times

by jain2016 » Mon Nov 16, 2015 11:29 pm

Hi Mitch ,

Why did you do A=1/2 pie. Please explain.

Also is there any other approach for this question?

Please advise.

Many thanks in advance.

SJ.

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Jim@StratusPrep: MBA Admissions Consultant; Posts: 2279; Joined: Fri Nov 11, 2011 7:51 amFollowed by: 266 members; Location: New York; Thanked: 660 times; GMAT Score:770

by Jim@StratusPrep » Tue Nov 17, 2015 8:43 am

1/2 pi is used because each is 1/2 of a circle with a diameter of 1.

didieravoaka-

1) it would have to be A + B + 2C = 15
2) should make sense from #1

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