Help needed with the following:
(x-y)^2 = 0.
I understand that this translates to (x-y)(x-y) = 0. But kaplan says that this is the same as (x-y) = 0, why is this.
Thanks
(x-y)^2 = 0.
I understand that this translates to (x-y)(x-y) = 0. But kaplan says that this is the same as (x-y) = 0, why is this.
Thanks












