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Help with simple maths problem

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
Source: — Quantitative Reasoning |

by b00ndgl » Thu Jan 11, 2007 1:19 pm
If (x-y)^2 = (x-y)(x-y)=0, then we can immediately say that (x-y)=0. This equation consists of the multiplication of two terms that are the same, so we need only consider one of the terms (since they are both the same).
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Re: Help with simple maths problem

by chandooed » Thu Jan 11, 2007 1:26 pm
(x-y)^2=0;
apply sqrt on both sides of the '=' sign
sqrt [ (x-y)^2 ] = sqrt (0); ( sqrt of (x-y)^2 is (x-y) & sqrt of 0 is 0)
so, (x-y) = 0.

Hope this helps.
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by wildrebel » Thu Jan 11, 2007 2:37 pm
In simpler terms,

if (x-y)^2 = 0,

that means (x-y)(x-y)=0

Simple logic- if ZERO is the product of two numbers, one or both of those numbers HAS to be ZERO.
For eg. (1)(0)=0, (0)(534)=0 or (0)(0)=0

In this case, since you're squaring (x-y), and the answer is 0, that means x-y HAS TO BE 0.

Other than the number 0, no other number can mathematically square to 0.

Hope that was easier to understand than lines of equations.
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