1st dice - can have 6 possible valuespemdas wrote:In how many ways four fair dices, which are numbered and tossed simultaneously, have different numbers?
2nd dice- can have 5
3rd dice- 4
4th dice-3
So total no would be = 6*5*4*3 = 360
Or u can also think it this way-
Select 4 different nos between 1 and 6 inclusive and arrange them amongst themselves = 6P4

















