Angle ADB and Angle ADC are supplementary i.e.
Angle ADB + Angle ADC =180
Angle ADB +60 =180
Angle ADB = 120
Sum of internal angles for a triangle ABD is 180.
On this basis Angle DAB = 180 -120 - 45 = 15
As line segment CD is twice of line segment DB. Angle CAD is 30.
Sum of internal angles for a triangle ACD is 180.
Angle ACD (x) = 180 - 60 - 30 = 90.
Answer is 90.
triangle problem
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tritrantran
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How did you get this?suragga wrote:
As line segment CD is twice of line segment DB. Angle CAD is 30.
