AbhishekRyu wrote:Ken has a group of coins worth $6.70. He has four times as many nickels as dimes, and twenty fewer quarters than nickels. How many quarters does he have?
A) 19
B) 18
C) 16
D) 15
E) 14
Let x = the NUMBER of dimes
So, 4x = the NUMBER of nickels
And 4x - 20 = the NUMBER of quarters
One dime is worth $0.1, so 0.10x = the total VALUE of the dimes (in dollars)
Likewise, (0.05)(4x) = the total VALUE of the nickels (in dollars)
And (0.25)(4x - 20) = the total VALUE of the quarters (in dollars)
The total VALUE of all coins is $6.70
So, we can write: 0.10x + (0.05)(4x) + (0.25)(4x - 20) = 6.70
Simplify to get: 0.10x + 0.20x + x - 5 = 6.70
Simplify again to get: 1.3x - 5 = 6.70
Add 5 to both sides to get: 1.3x = 11.70
Solve: x = 11.70/1.3 = 9
So, there are 9 DIMES, 36 nickels and 16 quarters.
Answer: C
Cheers,
Brent