Marion rented a car for $18.00

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pm; Followed by:23 members

Marion rented a car for $18.00

by BTGmoderatorDC » Sat Dec 30, 2017 3:07 am

Marion rented a car for $18.00 plus $0.10 per mile driven. Craig rented a car for $25.00 plus $0.05 per mile driven. If each drove d miles and each was charged exactly the same amount for the rental, then d equals

(A) 100

(B) 120

(C) 135

(D) 140

(E) 150

Can some experts show the best way to solve this problem?

OA D

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Source: Beat The GMAT — Problem Solving | Sat Dec 30, 2017 3:07 am

EconomistGMATTutor: GMAT Instructor; Posts: 555; Joined: Wed Oct 04, 2017 4:18 pm; Thanked: 180 times; Followed by:12 members

by EconomistGMATTutor » Sat Dec 30, 2017 2:31 pm

Marion rented a car for $18.00 plus $0.10 per mile driven. Craig rented a car for $25.00 plus $0.05 per mile driven. If each drove d miles and each was charged exactly the same amount for the rental, then d equals

(A) 100

(B) 120

(C) 135

(D) 140

(E) 150

Can some experts show the best way to solve this problem?

OA D

Hi lheiannie07,
Let's take a look at your question.

Marion rented a car for $18.00 plus $0.10 per mile driven. If 'c' represents the amount charges and 'd' represents the miles driven, we can write:
$$c=18+0.10d$$

Craig rented a car for $25.00 plus $0.05 per mile driven. We can write it as,
$$c=25+0.05d$$

If each was charged exactly the same amount for the rental, then,
$$18+0.10d=25+0.05d$$
$$0.10d-0.05d=25-18$$
$$0.05d=7$$
$$d=\frac{7}{0.05}=140$$

Therefore, Option D is correct.

Hope it helps.
I am available if you'd like any follow up.

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GMATWisdom: Master | Next Rank: 500 Posts; Posts: 100; Joined: Wed Nov 29, 2017 4:38 pm; Thanked: 14 times

by GMATWisdom » Sat Dec 30, 2017 5:42 pm

lheiannie07 wrote:Marion rented a car for $18.00 plus $0.10 per mile driven. Craig rented a car for $25.00 plus $0.05 per mile driven. If each drove d miles and each was charged exactly the same amount for the rental, then d equals

(A) 100

(B) 120

(C) 135

(D) 140

(E) 150

Can some experts show the best way to solve this problem?

OA D

we can easily solve this algebrically. but if give a little thinking we can do it orally as well.
Craig is initially taking $7 more than Marion . For both to get the same amount Marion should compensate from the rate
per kilometer which he charges more than Craig, As Marion is charging $ .05 per kilometer more than Craig he should drive
7/.05=140 kilometer for both to get the same amount .
Hence option D

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by Scott@TargetTestPrep » Sun Aug 18, 2019 6:23 pm

BTGmoderatorDC wrote:Marion rented a car for $18.00 plus $0.10 per mile driven. Craig rented a car for $25.00 plus $0.05 per mile driven. If each drove d miles and each was charged exactly the same amount for the rental, then d equals

(A) 100

(B) 120

(C) 135

(D) 140

(E) 150

Can some experts show the best way to solve this problem?

OA D