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Test Code 52, Section6, question 4

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Test Code 52, Section6, question 4

by irfan_m1973 » Tue Dec 01, 2009 11:12 pm
A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr

(B) 2 hr

(C) 2 1/2hr

(D) 6 hr

(E) 24 hr
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by papgust » Tue Dec 01, 2009 11:27 pm
IMO D

Total documents (n) = 148
Each document has avg of 10 pages and takes 15 seconds to print each page.

Total pages/total documents = Avg pages/document
Total pages/148 = 10
Total pages = 1480

1480 * 15 sec / 60 * 60 = 6 hrs (Approx.)

Please share the OA.
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by irfan_m1973 » Wed Dec 02, 2009 12:12 am
Hi papgust. Thanks for your reply. As you can see I am new to this forum, I do not know how to go about sharing tghe OA. Can you pl let me know the same? Thank you
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by haydieenano » Wed Dec 02, 2009 12:26 am
what does oa mean??..im just new here..

anyway i got the same answer..6 hrs..

thanks!
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by irfan_m1973 » Wed Dec 02, 2009 1:32 am
haydieenano wrote:what does oa mean??..im just new here..

anyway i got the same answer..6 hrs..

thanks!
OA is original answer...correct me if im wrong
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by papgust » Wed Dec 02, 2009 1:42 am
OA is official answer. The answer given by the source.

While posting the question, type your answer with spoiler (you can see a "Spoiler" button while you edit the post). This will hide the answer in your post.
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by GMATinsight » Thu Nov 12, 2015 6:35 am
irfan_m1973 wrote:A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr

(B) 2 hr

(C) 2 1/2hr

(D) 6 hr

(E) 24 hr

CONCEPT: [m][fraction](Machine_Power * Time)/Work[/fraction] = Constant[/m]
i.e. [m][fraction](M_1 * T_1)/W_1[/fraction] = [fraction](M_2 * T_2)/W_2[/fraction][/m]


Work ([m]W_2[/m]) = 148 Documents = 1480 Pages
Time ([m]T_2[/m]) = ?

[m][fraction](1 * 15)/1[/fraction] = [fraction](1 * T_2)/1480[/fraction][/m]

[m]T_2 = 1480*15 secs = 1480*15/3600 Hours = 6.16 Hours[/m]

Answer: Option D
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by Scott@TargetTestPrep » Tue Dec 12, 2017 6:21 am
irfan_m1973 wrote:A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr

(B) 2 hr

(C) 2 1/2hr

(D) 6 hr

(E) 24 hr
Since there are 10 pages in each of the 148 documents, there are a total of 148 x 10 = 1480 pages. Since it takes 15 seconds to print each page, it will take 15 x 1480 = 22,200 seconds to print all of the pages. Since there are 3,600 seconds in an hour, the time in hours is 22,200/3,600 = 222/36 = 37/6 = 6 â…™ hours, which is about 6 hours.

Answer: D

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