Graph Prob-- Need help

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Graph Prob-- Need help

by selango » Thu May 20, 2010 9:30 pm
SOURCE: OG 12, Prob:9

On the graph above,when x=1/2,y=2;and when x=1 y=1. The graph is symmetric with respect to the vertical line at x=2.
According to the graph when x=3 y=?

A) -1

B) -1/2

C) 0

D) 1/2

E) 1

Can anyone solve this in detail?
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by liferocks » Thu May 20, 2010 9:34 pm
The graph is symmetric with respect to the vertical line at x=2
this mean for x=2+a and x=2-a value of y will be same

if we take a=1..x=2+a=3 and x=2-a=1

so value of y at x=1 and x=3 will be same [spoiler]which is y=1[/spoiler]

Ans option E
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by selango » Thu May 20, 2010 9:44 pm
Thanks for the reply

Can you explain what s meant by symmetric in detail?

Is there any formula?

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by liferocks » Thu May 20, 2010 9:49 pm
selango wrote:Thanks for the reply

Can you explain what s meant by symmetric in detail?

Is there any formula?
symmetric means the graph will be mirror image wrt the line ie here the parabola has two halves wrts x=2 where one half is mirror image of the other taking x=2 as the mirror line.There is no formula for this as per my knowledge.
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by selango » Thu May 20, 2010 9:52 pm
Thanks

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by winnerhere » Sat May 14, 2011 10:33 pm
did anyone try to applu

y = ax^2 + bx + c formula

and derive a,b,c for the three equations and find the answer? The answer is different with this method.

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by Karly » Tue Jul 29, 2014 7:40 pm
winnerhere wrote:did anyone try to applu

y = ax^2 + bx + c formula

and derive a,b,c for the three equations and find the answer? The answer is different with this method.
I can prove that it is a mistake made by GMAC. I plugged in (1/2,2), (1,1) and (2,0) into the equation:y=ax^2+bx+c and I got when x=3, y should be equal to -5/3.

Did anyone else notice that?

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by [email protected] » Tue Jul 29, 2014 10:38 pm
Hi Karly,

The GMAT limits its Quant subject-matter; most of it can be handled by someone who's taken basic algebra and geometry in school. There are a few exceptions of course (probability, permutations, combinations, etc.), but there are certain categories that the GMAT will NEVER test you on (eg. Logarithms, Algebra 2, Trigonometry, Calculus, etc.).

The GMAT does NOT expect you to know how to graph a parabola, so using that formula was not a requirement to answer this question. You ARE expected to know what the word "symmetric" means though. That's essentially ALL this question is about. You can even "avoid the math" altogether (let's pretend that you don't know what the word "symmetric" means) and just use the drawing to estimate the answer.

Part of scoring at a high level on the GMAT is in learning how to answer the various question types in the most efficient ways possible. If you can answer a question in 3 minutes or in 1 minute, then you really have to do so in the 1-minute "way." Doing lots of complex math is rarely what is required to solve a Quant question, so make sure you're practicing more than just that approach.

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Rich
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by GMATinsight » Wed Jul 30, 2014 6:03 am
selango wrote:SOURCE: OG 12, Prob:9

On the graph above,when x=1/2,y=2;and when x=1 y=1. The graph is symmetric with respect to the vertical line at x=2.
According to the graph when x=3 y=?

A) -1

B) -1/2

C) 0

D) 1/2

E) 1

Can anyone solve this in detail?
Since the Graph is Symmetric about x=2 therefore the value of y if we moved an amount amount on right side of x=2 will be same as if we moved the same distance on the left side from x=2

x=3 is 1 unit to the right of x, where the value of y will be same as the value of y if we moved 1 unit to the left i.e. at x=1
at x=1, y = 1
therefore, at x = 3 also , y = 1

Answer: Option E
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by GMATinsight » Wed Jul 30, 2014 6:08 am
Karly wrote:
winnerhere wrote:did anyone try to applu

y = ax^2 + bx + c formula

and derive a,b,c for the three equations and find the answer? The answer is different with this method.
I can prove that it is a mistake made by GMAC. I plugged in (1/2,2), (1,1) and (2,0) into the equation:y=ax^2+bx+c and I got when x=3, y should be equal to -5/3.

Did anyone else notice that?
The graph intersect at x = 2 i.e. the equation has two roots and both are equal i.e. x=2
equation of the graph becomes
y = (x - 2)^2
i.e. y = x^2 - 4x + 4
at x = 3, y = 9-12+4 = 1

Answer : Option E
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by GMATinsight » Wed Jul 30, 2014 6:10 am
Hi Karly,

Please keep in mind that GMAC is NEVER wrong. These question are made scientifically and they don't have any potential to be incorrect.
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Graph Prob-- Need help

by Brent@GMATPrepNow » Fri Aug 01, 2014 3:03 pm
As Rich mentioned, you don't need to know how to find the equation of a parabola on the GMAT. All that matters is that parabolas are symmetrical about an axis.

For the visual learners out there, here's my solution:
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Cheers,
Brent
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by Matt@VeritasPrep » Sat Aug 02, 2014 11:02 am
Brent@GMATPrepNow wrote:As Rich mentioned, you don't need to know how to find the equation of a parabola on the GMAT. All that matters is that parabolas are symmetrical about an axis.
This is not current, I don't think. The 2014 GMAT does assume you know a number of things about parabolas, specifically:

* The impact of the a coefficient (what happens if it's negative, what happen if it's positive)
* The impact of the discriminant (specifically its relationship to the y-intercepts)
* The relationship between the roots of a quadratic and the intercepts of a parabola

and there may be other expectations as well.

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by Matt@VeritasPrep » Sat Aug 02, 2014 11:06 am
GMATinsight wrote:Hi Karly,

Please keep in mind that GMAC is NEVER wrong. These question are made scientifically and they don't have any potential to be incorrect.
This is not true. Any standardized test has the potential to err, and most of them make mistakes at some point. The LSAT seems to remove a question from scoring at least once a year due to error or ambiguity, and even a math test as venerable as the AMC has had this issue in the past, so I don't see why the GMAT is exempt.

The difference with the GMAT is that it is very hard to catch their test writers in a mistake, as you'd need to memorize the question, then somehow verify independently after the fact that it was wrong; the question will almost never be released for public scrutiny. (This lack of transparency is a major issue, in my opinion.)

That said, GMAT questions are very seldom wrong or flawed, as they go through many checks and reviews; I'd imagine fewer than 1% of questions on the actual GMAT are flawed or ambiguous. (In other words, if you think there's a flaw, YOU'RE probably wrong ... but not always!)

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by Brent@GMATPrepNow » Sat Aug 02, 2014 12:59 pm
Matt@VeritasPrep wrote:
Brent@GMATPrepNow wrote:As Rich mentioned, you don't need to know how to find the equation of a parabola on the GMAT. All that matters is that parabolas are symmetrical about an axis.
This is not current, I don't think. The 2014 GMAT does assume you know a number of things about parabolas, specifically:

1) The impact of the a coefficient (what happens if it's negative, what happen if it's positive)
2) The impact of the discriminant (specifically its relationship to the y-intercepts)
3) The relationship between the roots of a quadratic and the intercepts of a parabola

and there may be other expectations as well.
Hey Matt,

My point was more about whether or not we need to know how to find the equation of a parabola. That said, I consider point #3 relating more to finding the roots of an equation/x-intercepts than knowing how the graph of the parabola looks (although the concepts are linked).

As for point #2, I'm not sure what you mean by the relationship between the discriminant and the y-intercept. For any quadratic in the form y = ax² + bx + c, the y-intercept will be at (0, c). If you're referring to the x-intercept (and not the y-intercept), then points #2 and #3 are kind of the same and can be handled without knowing a great deal about how the parabola actually looks.

I'd be surprised to learn that test-takers are required to know how the a coefficient impacts the graph of a parabola, other than perhaps whether a is negative or positive (in which case students can just as easily easily plot a few points to see the effect). IF that is required knowledge, I'd say that's as far as the test-takers would go. That is, I don't believe we're required to know how the magnitude of a (i.e., y = 2x² - 3x + 1 vs y = x² - 3x + 1) affects the parabola.

Cheers,
Brent
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