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Easy, but can't solve this equation

Expert replies
by prince11 » Sat Sep 05, 2009 5:43 pm
Hi all,

can someone please show me how to solve this equation.

Thanks in advance and here is the problem

If x≠0 and X = square root(4xy-4y^2) , then, in terms of y, X =

a) 2y
b) y
c) y/2
d) -4y^2/1-2y
e) -2y
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Source: — Problem Solving |

by truplayer256 » Sat Sep 05, 2009 6:19 pm
x=sqrt(4xy-4y^2)

Square both sides to get:

x^2=4xy-4y^2

x^2-4xy+4y^2=0

(x-2y)(x-2y)=0

x-2y=0

x=2y

A
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