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\[ If\ \ 3^k+3^k=(3^9)^{3^9}-3^k,\ \ \ then\ \ \ \ k=? \]

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by VJesus12 » Thu Jun 14, 2018 1:05 am

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$$If\ \ 3^k+3^k=(3^9)^{3^9}-3^k,\ \ \ then\ \ \ \ k=?$$ (A) 11/3
(B) 11/2
(C) 242
(D) 3^10
(E) 3^11 - 1

The OA is the option E.

How can I rewrite the given expression to get the correct answer? I could solve the powers. <i class="em em-frowning"></i>
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Source: — Problem Solving |

by Vincen » Thu Jun 14, 2018 2:01 am
VJesus12 wrote:$$If\ \ 3^k+3^k=(3^9)^{3^9}-3^k,\ \ \ then\ \ \ \ k=?$$ (A) 11/3
(B) 11/2
(C) 242
(D) 3^10
(E) 3^11 - 1

The OA is the option E.

How can I rewrite the given expression to get the correct answer? I could solve the powers. <i class="em em-frowning"></i>
Hello Vjesus12.

You can rewrite the powers as follows: $$3^k+3^k=(3^9)^{3^9}-3^k\ \ \ \Rightarrow\ \ \ \ 2\cdot3^k=\left(3\right)^{9\cdot3^9}-3^k$$ $$\Rightarrow\ \ \ \ 2\cdot3^k+3^k=\left(3\right)^{3^2\cdot3^9}$$ $$\Rightarrow\ \ \ \ 3\cdot3^k=\left(3\right)^{3^{11}}$$ $$\Rightarrow\ \ \ \ 3^{k+1}=\left(3\right)^{3^{11}}$$ $$\Rightarrow\ \ k+1=3^{11}$$ $$\Rightarrow\ \ k=3^{11}-1.$$ That way we get that the correct answer is the option E .

I hope it helps you. <i class="em em-smiley"></i>
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by DrMaths » Thu Jun 14, 2018 3:41 am
3^k+3^k=(3^9)^3^9−3k
3^k+3^k+3^k=(3^3^2)^3^9
3(3^k) = (3)^3^(2+9)
3(3^k) = 3^3^(11)
(3^k) = 3^3^(11)-1
k = 3^(11)-1
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by Jeff@TargetTestPrep » Sun Jun 17, 2018 7:07 pm
VJesus12 wrote:$$If\ \ 3^k+3^k=(3^9)^{3^9}-3^k,\ \ \ then\ \ \ \ k=?$$ (A) 11/3
(B) 11/2
(C) 242
(D) 3^10
(E) 3^11 - 1
Simplifying we have:

3^k + 3^k + 3^k = (3^9)^(3^9)

3(3^k) = 3^(9 x 3^9)

3^(k + 1) = 3^(3^2 x 3^9)

k + 1 = 3^11

k = 3^11 - 1

Answer: E

Jeffrey Miller
Head of GMAT Instruction
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