To determine the y intercept, plug y = 0 . Why? Is dere any rule relating to this?qwe12 wrote:my way of solving this is as follows, if y = mx + c, is the equation of a line, where c is the y intercept.
from 1) m = 3c
=> y = 3cx + c, to determine the y intercept, plug y = 0
0 = c(3x + 1)
Here, we can 2 options c=0 and x can be anything
or 3x+1 = 0 and c can be anything.
NOT SUFFICIENT.
from 2)
y = m(-1/3) + c
y = -m/3 + c
so c = y + m/3, if y goes to 0, c = m/3, and m can be anything,
NOT SUFFICIENT.
Using (1) and (2) we find we have 2 equations and 3 unknowns.
y = 3cx + c
y = -m/3 + c
We need 3 equations to solve for 3 unknowns.
SO (E)
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What is the y-intercept?
This is wrong. To determine y intercept, you need to plugin x=0 . Since y intercept is the point where line cuts y axis. Similarly for finding the x intercept, you need to put y =0.To determine the y intercept, plug y = 0 . Why? Is dere any rule relating to this?
Its an inverse relationship.
Let me know, if anything requires clarity
















