median

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k.pankaj.r: Senior | Next Rank: 100 Posts; Posts: 50; Joined: Thu Dec 25, 2008 9:06 am; Thanked: 1 times

by k.pankaj.r » Mon Dec 05, 2011 6:26 pm

a,b and c are integers and a<b<c, S is the set of all integers from a to b, inclusive. Q is the set of all integers from b to c, inclusive. the median of the set S is (3/4)b. the median of the set Q is (7/8)c. if R is the set of all integers from a to c, inclusive, what fraction of c is the median of set R?

a) 3/8
b) 1/2
c) 11/16
d) 5/7
e) 3/4

OA C

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Source: Beat The GMAT — Problem Solving | Mon Dec 05, 2011 6:26 pm

GMATGuruNY: GMAT Instructor; Posts: 15539; Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members; Location: New York, NY; Thanked: 13060 times; GMAT Score:790

by GMATGuruNY » Mon Dec 05, 2011 6:52 pm

I posted a solution here:

https://www.beatthegmat.com/integers-nic ... 82287.html

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chieftang: Master | Next Rank: 500 Posts; Posts: 218; Joined: Wed Nov 23, 2011 8:05 pmFollowed by: 4 members; Thanked: 26 times

by chieftang » Mon Dec 05, 2011 6:54 pm

Median of a -> b = (a+b)/2 = (3/4)*b
Median of b -> c = (b+c)/2 = (7/8)*c
Median of a -> c = (a+c)/2 = ?

Solve for a in terms of c:
a = (3/8)*c

Plug it in:
((3/8)*c + c)/2 = (11/16)*c

ANSWER: C

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k.pankaj.r: Senior | Next Rank: 100 Posts; Posts: 50; Joined: Thu Dec 25, 2008 9:06 am; Thanked: 1 times

by k.pankaj.r » Mon Dec 05, 2011 7:35 pm

thanks mitch..the post helped a lot..

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by [email protected] » Sat Dec 24, 2011 4:57 am

chieftang's solution is better!!!

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