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if xy=1 what is the value of 2^(x+y)^2 / 2^(x-y)^2
ans.16
can someone pls explain
ans.16
can someone pls explain
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Simplifying the given expression, we have:yvonne12 wrote:if xy=1 what is the value of 2^(x+y)^2 / 2^(x-y)^2
ans.16

2^(X+Y)²/ 2^(X-Y)² = 2^(X² + 2XY + Y²)/ 2^(X² - 2XY + Y²)if XY=1 then what is the value of 2^(X+Y)²/ 2^(X-Y)²
A) 2
B) 4
C) 8
D) 16
E) 32
Brent@GMATPrepNow wrote:Here's the full question...2^(X+Y)²/ 2^(X-Y)² = 2^(X² + 2XY + Y²)/ 2^(X² - 2XY + Y²)if XY=1 then what is the value of 2^(X+Y)²/ 2^(X-Y)²
A) 2
B) 4
C) 8
D) 16
E) 32
= 2^(4XY) [after we subtract exponents]
= 2^4 [since XY = 1]
= 16
Answer: D
Cheers,
Brent
Let x=y=1.If XY=1 then what is the value of 2^(X+Y)^2/ 2^(X-Y)2^2
1)2
2) 4
3) 8
4) 16
5) 32
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