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substraction

by jaijune » Sat Apr 07, 2012 7:44 am
Dear All,
How to solve the below problem.

Substract 27 5/4 from 43 1/6

A)15
B)15 5/84
C)15 8/24
D)15 15/20
E)15 17/21

Thanks in advance.
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by Bill@VeritasPrep » Sat Apr 07, 2012 8:20 am
Is the first number supposed to be 27 4/5?
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by ronnie1985 » Sat Apr 07, 2012 8:28 am
43 1/6 = 41 13/6
27 5/4 = 27 5/4
Subtract = (41-27) + (13/6-5/4) = 14 + (26-15)/12 = 14 11/12
Something wrong in the question.
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by jaijune » Sat Apr 07, 2012 8:31 am
Bill@VeritasPrep wrote:Is the first number supposed to be 27 4/5?
43 1/6 is the first number.

Thank you
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by Bill@VeritasPrep » Sat Apr 07, 2012 8:34 am
This is what I meant:
Substract 27 5/4 from 43 1/6
None of those answers are possible with 27 5/4.
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